javascript add nd st th to number
function ordinal(number) {
const english_ordinal_rules = new Intl.PluralRules("en", {
type: "ordinal"
});
const suffixes = {
one: "st",
two: "nd",
few: "rd",
other: "th"
}
const suffix = suffixes[english_ordinal_rules.select(number)];
return (number + suffix);
}
ordinal(3); /* output: 3rd */
ordinal(111); /* output: 111th */
ordinal(-1); /* output: -1st */add st nd rd th javascript
The rules are as follows:
1. st is used with numbers ending in 1 (e.g. 1st, pronounced first)
2. nd is used with numbers ending in 2 (e.g. 92nd, pronounced ninety-second)
3. rd is used with numbers ending in 3 (e.g. 33rd, pronounced thirty-third)
Note* : As an exception to the above rules, all the "teen" numbers ending with 11, 12
or 13 use -th (e.g. 11th, pronounced eleventh, 112th, pronounced one hundred
[and] twelfth)
th is used for all other numbers (e.g. 9th, pronounced ninth).
The following JavaScript code (rewritten in Jun '14) accomplishes this:
function ordinal_suffix_of(i) {
var j = i % 10,
k = i % 100;
if (j == 1 && k != 11) {
return i + "st";
}
if (j == 2 && k != 12) {
return i + "nd";
}
if (j == 3 && k != 13) {
return i + "rd";
}
return i + "th";
}Copyright © 2021 Codeinu
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