Answers for "javascript queryselectorall event listener"

4

document queryselector click event

const buttons = document.querySelectorAll("#select .button")
for (const button of buttons) {
  button.addEventListener('click', function(event) {
    //...
  })
}
Posted by: Guest on April-07-2020
1

query selector click event

var deleteLink = document.querySelector('.delete');

deleteLink.addEventListener('click', function(event) {
    event.preventDefault();

    var choice = confirm("sure u want to delete?");
    if (choice) {
        return true;
    }
});
Posted by: Guest on April-11-2020
0

Add click event to querySelectorAll js

var deleteLinks = document.querySelectorAll('.delete');

Array.from(deleteLinks).forEach(link => {
    link.addEventListener('click', function(event) {
        if (!confirm(`sure u want to delete ${this.title}`)) {
            event.preventDefault();
        }
    });
});
Posted by: Guest on August-29-2021
3

javascript queryselectorall

<article class="article first">
  <div class="wrapper"> 
    <div class="oferts"> 
      <div class="pro"></div> 
      <h1>This is the Pro Version</h1>  
    </div>
    <div class="oferts"> 
      <div class="normal"></div> 
      <h1>This is the normal Version</h1>  
    </div>
  </div>
</article>


// You will get a NodeList as Output
// Try to do : console.log(typeof(oferts)) And you will see the type
<script>
var articleFirst = document.querySelectorAll("article.first");
console.log(articleFirst)
var oferts = articleFirst[0].querySelectorAll(".oferts");
console.log(oferts)
</script>
Posted by: Guest on November-16-2020
0

js queryselectorall

elementList = parentNode.querySelectorAll(selectors);
Posted by: Guest on January-12-2021

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