Answers for "queryselectorall jquery"

1

queryselectorall

//To obtain a NodeList of all of the <p> elements in the document:
const matches = document.querySelectorAll("p");

//This example returns a list of all <div> elements within the document with a class of either note or alert:
const matches = document.querySelectorAll("div.note, div.alert");

//Here, we get a list of <p> elements whose immediate parent element is a <div> with the class highlighted and which are located inside a container whose ID is test.
const container = document.querySelector("#test");
const matches = container.querySelectorAll("div.highlighted > p");
Posted by: Guest on July-30-2021
1

js querySelectorAll

// https://www.google.com/
// this puts a border around the 'a' tags of 'Google offered in' section.

// within this id find all the 'a' tags
var languages = document.querySelectorAll("#SIvCob a");


// loop through all the a tags a add a border to the tags
for(var i = 0; i < languages.length; i++){
    document.querySelectorAll("#SIvCob a")[i].style.border = "1px solid black";

}
Posted by: Guest on May-22-2021
3

javascript queryselectorall

<article class="article first">
  <div class="wrapper"> 
    <div class="oferts"> 
      <div class="pro"></div> 
      <h1>This is the Pro Version</h1>  
    </div>
    <div class="oferts"> 
      <div class="normal"></div> 
      <h1>This is the normal Version</h1>  
    </div>
  </div>
</article>


// You will get a NodeList as Output
// Try to do : console.log(typeof(oferts)) And you will see the type
<script>
var articleFirst = document.querySelectorAll("article.first");
console.log(articleFirst)
var oferts = articleFirst[0].querySelectorAll(".oferts");
console.log(oferts)
</script>
Posted by: Guest on November-16-2020
0

select all elements javascript

var elements = document.getElementsByTagName("*");
Posted by: Guest on November-24-2020
0

queryselector for jquery

var x = $(".yourclass")[0];
console.log('jq' + x);
var y = document.querySelector(".yourclass");
console.log('js' + y);
Posted by: Guest on April-22-2020
0

js queryselectorall

elementList = parentNode.querySelectorAll(selectors);
Posted by: Guest on January-12-2021

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