javascript check if number
function isNumber(n) { return /^-?[\d.]+(?:e-?\d+)?$/.test(n); }
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isNumber('123'); // true
isNumber('123abc'); // false
isNumber(5); // true
isNumber('q345'); // false
isNumber(null); // false
isNumber(undefined); // false
isNumber(false); // false
isNumber(' '); // falsecompare NaN in javascript if condititon
// Use isNaN()
// In javascript compare NaN direct alweys return false
let num1 = Number("Vishal");
// This code never work
if(num1 == NaN){ // Direct compare NaN alweys return false so use isNaN() function
....... Your Code .......
}
// This code work
if(isNaN(num1){
.........Your Code .......
}Copyright © 2021 Codeinu
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