Answers for "filter duplicate array object javascript"

1

how to remove duplicate array object in javascript

let days = ["senin","senin","selasa","selasa","rabu","kamis", "rabu"];
let fullname = [{name: "john"}, {name: "jane"}, {name: "imelda"}, {name: "john"},{name: "jane"}];

// REMOVE DUPLICATE FOR ARRAY LITERAL
const arrOne = new Set(days);
console.log(arrOne);

const arrTwo = days.filter((item, index) => days.indexOf(item) == index);
console.log(arrTwo);


// REMOVE DUPLICATE FOR ARRAY OBJECT
const arrObjOne = [...new Map(person.map(item => [JSON.stringify(item), item])).values()];
console.log(arrObjOne);

const arrObjTwo = Array.from(new Set(person.map(JSON.stringify))).map(JSON.parse);
console.log(arrObjTwo);
Posted by: Guest on April-22-2020
1

remove duplicate objects based on id from array angular 8

function getUnique(arr, comp) {

                    // store the comparison  values in array
   const unique =  arr.map(e => e[comp])

                  // store the indexes of the unique objects
                  .map((e, i, final) => final.indexOf(e) === i && i)

                  // eliminate the false indexes & return unique objects
                 .filter((e) => arr[e]).map(e => arr[e]);

   return unique;
}

console.log(getUnique(arr,'id'));
Posted by: Guest on November-09-2020
-1

remove duplicates from array of objects javascript

let arr = [{name: "john"}, {name: "jane"}, {name: "imelda"}, {name: "john"}];

const uniqueArray = arr.filter((v,i,a)=>a.findIndex(t=>(t.name===v.name))===i)
console.log(uniqueArray);
Posted by: Guest on June-21-2021
0

remove duplicates objects from array javascript

arr.reduce((acc, current) => {
  const x = acc.find(item => item.id === current.id);
  if (!x) {
    return acc.concat([current]);
  } else {
    return acc;
  }
}, []);
Posted by: Guest on November-09-2020
-1

remove duplicates objects from array javascript

function remove_duplicate_objects(data,prop) {
    var seen = {};
    data = data.filter(function (entry) {
      if (seen.hasOwnProperty(entry[prop])) {
        return false;
      }

      seen[entry.prop] = entry;
      return true;
    });
    return data
  }

const new_array = remove_duplicate_objects([array with objects inside])
Posted by: Guest on February-23-2021

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