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Answers for "jquery get url parameters"

Javascript
8

jquery get parameter from url

function GetUrlParameter(sParam)

{
    var sPageURL = window.location.search.substring(1);

    var sURLVariables = sPageURL.split('&');

    for (var i = 0; i < sURLVariables.length; i++)
    {
        var sParameterName = sURLVariables[i].split('=');

        if (sParameterName[0] == sParam)

        {
            return sParameterName[1];
        }
    }
}

And this is how you can use this function assuming the URL is,
http://dummy.com/?technology=jquery&blog=jquerybyexample.

var tech = GetUrlParameter('technology');
var blog = GetUrlParameter('blog');
Posted by: Guest on June-30-2020
0

jquery get parameter from url

function getUrlParameter(name, url) {
    if (!url) {
        url = window.location.href;
    }
    name = name.replace(/[\[]/, '\\[').replace(/[\]]/, '\\]');
    var regex = new RegExp('[\\?&]' + name + '=([^&#]*)');
    var results = regex.exec(url);
    return results === null ? '' : decodeURIComponent(results[1].replace(/\+/g, ' '));
}


//url = abc.com?techonology=software&blog=test
var tech = getUrlParameter('technology');
var blog = getUrlParameter('blog');
Posted by: Guest on September-15-2021
0

how to get url parameter using jquery or plain javascript

var getUrlParameter = function getUrlParameter(sParam) {
    var sPageURL = window.location.search.substring(1),
        sURLVariables = sPageURL.split('&'),
        sParameterName,
        i;

    for (i = 0; i < sURLVariables.length; i++) {
        sParameterName = sURLVariables[i].split('=');

        if (sParameterName[0] === sParam) {
            return typeof sParameterName[1] === undefined ? true : decodeURIComponent(sParameterName[1]);
        }
    }
    return false;
};
And this is how you can use this function assuming the URL is,
http://dummy.com/?technology=jquery&blog=jquerybyexample.

var tech = getUrlParameter('technology');
var blog = getUrlParameter('blog');
Posted by: Guest on June-04-2021

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