Answers for "js async loop"

14

js for loop

var i; //defines i
for (i = 0; i < 5; i++) { //starts loop
  console.log("The Number Is: " + i); //What ever you want
}; //ends loop
//Or:
console.log("The Number Is: " + 0);
console.log("The Number Is: " + 1);
console.log("The Number Is: " + 2);
console.log("The Number Is: " + 3);
console.log("The Number Is: " + 4);
//They do the same thing!
//Hope I helped!
Posted by: Guest on June-21-2020
2

async for loop

(async function loop() {
    for (let i = 0; i < 10; i++) {
        await new Promise(resolve => setTimeout(resolve, Math.random() * 1000));
        console.log(i);
    }
})();
Posted by: Guest on August-19-2020
4

loop with await in js

const dummyfunction = async () => {
	for (item of items) {
      	// Until promise returns,
      	// The loop waits here!
      	await turtle();
    }
}
Posted by: Guest on June-21-2021
2

async await in forloops

// Series loop
async (items) => {
  for (let i = 0; i < items.length; i++) {
  	
    // for loop will wait for promise to resolve
    const result = await db.get(items[i]);
    console.log(result);
  }
}

// Parallel loop
async (items) => {
  let promises = [];
  
  // all promises will be added to array in order
  for (let i = 0; i < items.length; i++) {
    promises.push(db.get(items[i]));
  }
  
  // Promise.all will await all promises in the array to resolve
  // then it will itself resolve to an array of the results. 
  // results will be in order of the Promises passed, 
  // regardless of completion order
  
  const results = await Promise.all(promises);
  console.log(results);
}
Posted by: Guest on May-15-2020
0

wait for loop to finish javascript

async function processArray(array) {
  // map array to promises
  const promises = array.map(delayedLog);
  // wait until all promises are resolved
  await Promise.all(promises);
  console.log('Done!');
}
Posted by: Guest on June-19-2020
-2

loop async javascript

const mapLoop = async _ => {
  console.log('Start')

  const numFruits = await fruitsToGet.map(async fruit => {
    const numFruit = await getNumFruit(fruit)
    return numFruit
  })

  console.log(numFruits)

  console.log('End')
}
Posted by: Guest on July-03-2020

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