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Answers for "iterate over array"

Javascript
32

javascript loop through array

var data = [1, 2, 3, 4, 5, 6];

// traditional for loop
for(let i=0; i<=data.length; i++) {
  console.log(data[i])  // 1 2 3 4 5 6
}

// using for...of
for(let i of data) {
	console.log(i) // 1 2 3 4 5 6
}

// using for...in
for(let i in data) {
  	console.log(i) // Prints indices for array elements
	console.log(data[i]) // 1 2 3 4 5 6
}

// using forEach
data.forEach((i) => {
  console.log(i) // 1 2 3 4 5 6
})
// NOTE ->  forEach method is about 95% slower than the traditional for loop

// using map
data.map((i) => {
  console.log(i) // 1 2 3 4 5 6
})
Posted by: Guest on December-18-2020
11

javascript iterate array

let array = ['Item 1', 'Item 2', 'Item 3'];

// Here's 4 different ways
for (let index = 0; index < array.length; index++) {
  console.log(array[index]);
}

for (let index in array) {
  console.log(array[index]);
}

for (let value of array) {
  console.log(value); // Will log each value
}

array.forEach((value, index) => {
  console.log(index); // Will log each index
  console.log(value); // Will log each value
});
Posted by: Guest on March-26-2020
13

loop through an array javascript

let array = ['Item 1', 'Item 2', 'Item 3'];

// Here's 4 different ways
for (let index = 0; index < array.length; index++) {
  console.log(array[index]);
}

for (let index in array) {
  console.log(array[index]);
}

for (let value of array) {
  console.log(value); // Will log value in array
}

array.forEach((value, index) => {
  console.log(index); // Will log each index
  console.log(value); // Will log each value
});
Posted by: Guest on March-25-2020
10

iterate array javascript

array = [ 1, 2, 3, 4, 5, 6 ]; 
for (index = 0; index < array.length; index++) { 
    console.log(array[index]); 
}
Posted by: Guest on November-30-2019
7

iterate through array javascript

const array = ["one", "two", "three"]
array.forEach(function (item, index) {
  console.log(item, index);
});
Posted by: Guest on May-31-2020
5

python for loop with array

foo = ['foo', 'bar']
for i in foo:
  print(i) #outputs 'foo' then 'bar'
for i in range(len(foo)):
  print(foo[i]) #outputs 'foo' then 'bar'
i = 0
while i < len(foo):
  print(foo[i]) #outputs 'foo' then 'bar'
Posted by: Guest on July-18-2020

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