Answers for "ajax call on scroll down"

1

ajax call to load a page on scrolling

$(document).ready(function(){
 
 $(window).scroll(function(){
 
  var position = $(window).scrollTop();
  var bottom = $(document).height() - $(window).height();

  if( position == bottom ){

   var row = Number($('#row').val());
   var allcount = Number($('#all').val());
   var rowperpage = 3;
   row = row + rowperpage;

   if(row <= allcount){
    $('#row').val(row);
    $.ajax({
     url: 'fetch_details.php',
     type: 'post',
     data: {row:row},
     success: function(response){
      $(".post:last").after(response).show().fadeIn("slow");
     }
    });
   }
  }

 });
 
});
Posted by: Guest on October-22-2020
0

ajax call to load a page on scrolling

<div class="container">

<?php

 include "config.php";

 // Row per page
 $rowperpage = 3;

 // counting total number of posts
 $allcount_query = "SELECT count(*) as allcount FROM posts";
 $allcount_result = mysqli_query($con,$allcount_query);
 $allcount_fetch = mysqli_fetch_array($allcount_result);
 $allcount = $allcount_fetch['allcount'];

 // select first 3 posts
 $query = "select * from posts order by id asc limit 0,$rowperpage ";
 $result = mysqli_query($con,$query);

 while($row = mysqli_fetch_array($result)){

   $id = $row['id'];
   $title = $row['title'];
   $content = $row['description'];
   $shortcontent = substr($content, 0, 160)."...";
   $link = $row['link'];
 ?>

   <div class="post" id="post_<?php echo $id; ?>">
     <h1><?php echo $title; ?></h1>
     <p>
       <?php echo $shortcontent; ?>
     </p>
     <a href="<?= $link ?>" target="_blank" class="more">More</a>
   </div>

 <?php
 }
 ?>

 <input type="hidden" id="row" value="0">
 <input type="hidden" id="all" value="<?php echo $allcount; ?>">

</div>
Posted by: Guest on October-22-2020
0

ajax call to load a page on scrolling

<?php

$host = "localhost"; /* Host name */
$user = "root"; /* User */
$password = ""; /* Password */
$dbname = "tutorial"; /* Database name */

$con = mysqli_connect($host, $user, $password,$dbname);

// Check connection
if (!$con) {
  die("Connection failed: " . mysqli_connect_error());
}
Posted by: Guest on October-22-2020

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