Answers for "ajax call post"

23

jquery ajax post example

var formData = {name:"John", surname:"Doe", age:"31"}; //Array 

$.ajax({
    url : "https://example.com/rest/getData", // Url of backend (can be python, php, etc..)
    type: "POST", // data type (can be get, post, put, delete)
    data : formData, // data in json format
  	async : false, // enable or disable async (optional, but suggested as false if you need to populate data afterwards)
    success: function(response, textStatus, jqXHR) {
    	console.log(response);
    },
    error: function (jqXHR, textStatus, errorThrown) {
		console.log(jqXHR);
      	console.log(textStatus);
      	console.log(errorThrown);
    }
});
Posted by: Guest on March-10-2020
4

jquery post

$.post( "test.php", { name: "John", time: "2pm" })
  .done(function( data ) {
    alert( "Data Loaded: " + data );
  });
Posted by: Guest on September-17-2020
3

ajax data post call in javascript

$.ajax({
   url: 'ajaxfile.php',
   type: 'post',
   data: {name:'yogesh',salary: 35000,email: '[email protected]'},
   success: function(response){

   }
});
Posted by: Guest on October-27-2020
1

ajax post

var myKeyVals = { A1984 : 1, A9873 : 5, A1674 : 2, A8724 : 1, A3574 : 3, A1165 : 5 }



var saveData = $.ajax({
      type: 'POST',
      url: "someaction.do?action=saveData",
      data: myKeyVals,
      dataType: "text",
      success: function(resultData) { alert("Save Complete") }
});
saveData.error(function() { alert("Something went wrong"); });
Posted by: Guest on October-05-2021
15

ajax jquery post

$.ajax({

   url     : "file.php",
   method  : "POST",

       data: { 
         //key                      :   value 
         action                   	:   action , 
         key_1   					:   value_key_1,
         key_2   					:   value_key_2
       }
   })

   .fail(function() { return false; })
	// Appel OK
   .done(function(data) {

   console.log(data);

 });
Posted by: Guest on May-05-2020
0

javascript ajax post

<!DOCTYPE html>
<html>
<body>

<h1>The XMLHttpRequest Object</h1>

<p id="demo">Let AJAX change this text.</p>

<button type="button" onclick="loadDoc()">Change Content</button>

<script>
function loadDoc() {
  var xhttp = new XMLHttpRequest();
  xhttp.open("GET", "ajax_info.txt", false);
  xhttp.send();
  document.getElementById("demo").innerHTML = xhttp.responseText;
}
</script>

</body>
</html>
Posted by: Guest on July-21-2021

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