Answers for "javascript jquery ajax"

2

jquery ajax

$.ajax({
        url: url,
        dataType: "json",
        type: "Post",
        async: true,
        data: { },
        success: function (data) {
           
        },
        error: function (xhr, exception) {
            var msg = "";
            if (xhr.status === 0) {
                msg = "Not connect.\n Verify Network." + xhr.responseText;
            } else if (xhr.status == 404) {
                msg = "Requested page not found. [404]" + xhr.responseText;
            } else if (xhr.status == 500) {
                msg = "Internal Server Error [500]." +  xhr.responseText;
            } else if (exception === "parsererror") {
                msg = "Requested JSON parse failed.";
            } else if (exception === "timeout") {
                msg = "Time out error." + xhr.responseText;
            } else if (exception === "abort") {
                msg = "Ajax request aborted.";
            } else {
                msg = "Error:" + xhr.status + " " + xhr.responseText;
            }
           
        }
    });
Posted by: Guest on February-15-2021
15

jquery ajax

$.ajax({

   url     : "file.php",
   method  : "POST",

       data: { 
         //key                      :   value 
         action                   	:   action , 
         key_1   					:   value_key_1,
         key_2   					:   value_key_2
       }
   })

   .fail(function() { return false; })
	// Appel OK
   .done(function(data) {

   console.log(data);

 });
Posted by: Guest on May-05-2020
2

js ajax

// For a plain JS solution, use these functions:

function _GET_REQUEST(url, response) {
  var xhttp;
  if (window.XMLHttpRequest) {
    xhttp = new XMLHttpRequest();
  } else {
    xhttp = new ActiveXObject("Microsoft.XMLHTTP");
  }

  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      response(this.responseText);
    }
  };

  xhttp.open("GET", url, true);
  xhttp.send();
}

function _POST_REQUEST(url, params, response) {
  var xhttp;
  if (window.XMLHttpRequest) {
    xhttp = new XMLHttpRequest();
  } else {
    xhttp = new ActiveXObject("Microsoft.XMLHTTP");
  }

  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      response(this.responseText);
    }
  };

  xhttp.open("POST", url, true);
  xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
  xhttp.send(params);
}

// and apply like this:
_GET_REQUEST('http://someurl', (response) => {
	// do something with variable response
});
_POST_REQUEST('http://someurl', 'paramx=y', (response) => {
	// do something with variable response
});
Posted by: Guest on October-25-2020

Code answers related to "Javascript"

Browse Popular Code Answers by Language