Answers for "what are ajax requests"

6

ajax syntax in javascript

var id = empid;

$.ajax({
    type: "POST",
    url: "../Webservices/EmployeeService.asmx/GetEmployeeOrders",
    data: "{empid: " + empid + "}",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: function(result){
        alert(result.d);
        console.log(result);
    }
});
Posted by: Guest on September-30-2020
3

how to make ajax request javascript

//Change the text of a <div> element using an AJAX //request:
//using JQuery


$("button").click(function(){
  $.ajax({url: "demo_test.txt", success: function(result){
    $("#div1").html(result);
  }});
});



//To send a request to a server, we use the open() //and send() methods of the XMLHttpRequest object:
// Javascript


xhttp.open("GET", "ajax_info.txt", true);
xhttp.send();

//example below
<html>
<body>

<h1>The XMLHttpRequest Object</h1>

<button type="button" onclick="loadDoc()">Request data</button>

<p id="demo"></p>


<script>
function loadDoc() {
  var xhttp = new XMLHttpRequest();
  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      document.getElementById("demo").innerHTML = this.responseText;
    }
  };
  xhttp.open("GET", "demo_get.asp", true);
  xhttp.send();
}
</script>

</body>
</html>
Posted by: Guest on January-17-2020
-1

what is ajax call

AJAX is allowing the Web page to retrieve small amounts of data from the
server without reloading the entire page. It is used for creating
fast and dynamic web pages.
There are several Wait methods I use to handle
AJAX calls. I add these pieces of code to my AJAX
testing code to handle it.
1. Explicit Waits
webdriver driver = new firefoxdriver();
driver.get("http://somedomain/url_that_delays_loading");
webelement mydynamicelement = (new webdriverwait(driver,10))
.until(expectedconditions.presenceofelementlocated(by.id("myd
ynamicelement")));
2. Implicit Waits
I also go for Implicit Waits, where I can decide on a
certain amount of time require WebDriver to poll the DOM for.  
 In this case your WebDriver will keep looking for an element(s),
 if it had been unavailable immediately. The default
time is set as 0, which can be easily adjusted as you may prefer.
In addition, this set wait time lasts as long as your browser is
open, so the time to search for any element on the page will be
the same.
webdriver driver = new firefoxdriver();
driver.manage().timeouts().implicitlywait(10,
timeunit.seconds);
driver.get("http://somedomain/url_that_delays_loading");
webelement mydynamicelement =
driver.findelement(by.id("mydynamicelement"));
Posted by: Guest on December-04-2020

Code answers related to "Javascript"

Browse Popular Code Answers by Language