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Answers for "js ajax post"

Javascript
23

jquery ajax post example

var formData = {name:"John", surname:"Doe", age:"31"}; //Array 

$.ajax({
    url : "https://example.com/rest/getData", // Url of backend (can be python, php, etc..)
    type: "POST", // data type (can be get, post, put, delete)
    data : formData, // data in json format
  	async : false, // enable or disable async (optional, but suggested as false if you need to populate data afterwards)
    success: function(response, textStatus, jqXHR) {
    	console.log(response);
    },
    error: function (jqXHR, textStatus, errorThrown) {
		console.log(jqXHR);
      	console.log(textStatus);
      	console.log(errorThrown);
    }
});
Posted by: Guest on March-10-2020
2

ajax data post call in javascript

$.ajax({
   url: 'ajaxfile.php',
   type: 'post',
   data: {name:'yogesh',salary: 35000,email: '[email protected]'},
   success: function(response){

   }
});
Posted by: Guest on October-27-2020
0

make ajax request post jquery

$.ajax({
  method: "POST",
  url: "some.php",
  data: { name: "John", location: "Boston" }
})
Posted by: Guest on July-21-2020
2

javascript send post data with ajax

function makeRequest (method, url, data) {
  return new Promise(function (resolve, reject) {
    var xhr = new XMLHttpRequest();
    xhr.open(method, url);
    xhr.onload = function () {
      if (this.status >= 200 && this.status < 300) {
        resolve(xhr.response);
      } else {
        reject({
          status: this.status,
          statusText: xhr.statusText
        });
      }
    };
    xhr.onerror = function () {
      reject({
        status: this.status,
        statusText: xhr.statusText
      });
    };
    if(method=="POST" && data){
        xhr.send(data);
    }else{
        xhr.send();
    }
  });
}

//POST example
var data={"person":"john","balance":1.23};
makeRequest('POST', "https://www.codegrepper.com/endpoint.php?param1=yoyoma",data).then(function(data){
              var results=JSON.parse(data);
});
Posted by: Guest on August-02-2019
-1

jquery ajax post

// Variable to hold request
var request;

// Bind to the submit event of our form
$("#foo").submit(function(event){

    // Prevent default posting of form - put here to work in case of errors
    event.preventDefault();

    // Abort any pending request
    if (request) {
        request.abort();
    }
    // setup some local variables
    var $form = $(this);

    // Let's select and cache all the fields
    var $inputs = $form.find("input, select, button, textarea");

    // Serialize the data in the form
    var serializedData = $form.serialize();

    // Let's disable the inputs for the duration of the Ajax request.
    // Note: we disable elements AFTER the form data has been serialized.
    // Disabled form elements will not be serialized.
    $inputs.prop("disabled", true);

    // Fire off the request to /form.php
    request = $.ajax({
        url: "/form.php",
        type: "post",
        data: serializedData
    });

    // Callback handler that will be called on success
    request.done(function (response, textStatus, jqXHR){
        // Log a message to the console
        console.log("Hooray, it worked!");
    });

    // Callback handler that will be called on failure
    request.fail(function (jqXHR, textStatus, errorThrown){
        // Log the error to the console
        console.error(
            "The following error occurred: "+
            textStatus, errorThrown
        );
    });

    // Callback handler that will be called regardless
    // if the request failed or succeeded
    request.always(function () {
        // Reenable the inputs
        $inputs.prop("disabled", false);
    });

});
Posted by: Guest on December-23-2020
0

javascript ajax post

<!DOCTYPE html>
<html>
<body>

<h1>The XMLHttpRequest Object</h1>

<p id="demo">Let AJAX change this text.</p>

<button type="button" onclick="loadDoc()">Change Content</button>

<script>
function loadDoc() {
  var xhttp = new XMLHttpRequest();
  xhttp.open("GET", "ajax_info.txt", false);
  xhttp.send();
  document.getElementById("demo").innerHTML = xhttp.responseText;
}
</script>

</body>
</html>
Posted by: Guest on July-21-2021

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