Answers for "get url params in javascript"

29

get parameter from the actual url javascript

// https://testsite.com/users?page=10&pagesize=25&order=asc
const urlParams = new URLSearchParams(window.location.search);
const pageSize = urlParams.get('pageSize');
Posted by: Guest on December-04-2020
9

js get url parameter

const queryString = window.location.search;
const urlParams = new URLSearchParams(queryString);
const code = urlParams.get('code')
Posted by: Guest on October-18-2020
1

get url query params js

const urlParams = new URLSearchParams(window.location.search);
const myParam = urlParams.get('myParam');
Posted by: Guest on July-26-2020
7

get parameters from url

var url_string = "http://www.example.com/t.html?a=1&b=3&c=m2-m3-m4-m5"; //window.location.href
var url = new URL(url_string);
var c = url.searchParams.get("c");
console.log(c);
Posted by: Guest on July-09-2020
0

get url params with js

const queryString = window.location.search;

const urlParams = new URLSearchParams(queryString);

const page_type = urlParams.get('page_type')

console.log(page_type);
Posted by: Guest on August-08-2021
2

javascript get parameter

let params = {};
window.location.search.slice(1).split('&').forEach(elm => {
  if (elm === '') return;
  let spl = elm.split('=');
  const d = decodeURIComponent;
  params[d(spl[0])] = (spl.length >= 2 ? d(spl[1]) : true);
});

// https://example.com/?foo=bar&best%20food=D%C3%B6ner
params['foo'] // bar
params['best food'] // Döner
Posted by: Guest on June-11-2020

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