Answers for "typescript get url parameter"

29

get parameter from the actual url javascript

// https://testsite.com/users?page=10&pagesize=25&order=asc
const urlParams = new URLSearchParams(window.location.search);
const pageSize = urlParams.get('pageSize');
Posted by: Guest on December-04-2020
2

typescript read url parameters

// get all search params (including ?)
const queryString = window.location.search;
// it will look like this: ?product=shirt&color=blue&newuser&size=m

// parse the query string's paramters
const urlParams = new URLSearchParams(queryString);

// To get a parameter simply write something like the follwing
const paramValue = urlParams.get('yourParam');
Posted by: Guest on June-04-2021
9

js get url parameter

const queryString = window.location.search;
const urlParams = new URLSearchParams(queryString);
const code = urlParams.get('code')
Posted by: Guest on October-18-2020
0

get url params in typescript

import {Router, ActivatedRoute, Params} from '@angular/router';
import {OnInit, Component} from '@angular/core';

@Component({...})
export class MyComponent implements OnInit {

  constructor(private activatedRoute: ActivatedRoute) {}

  ngOnInit() {
    // Note: Below 'queryParams' can be replaced with 'params' depending on your requirements
    this.activatedRoute.queryParams.subscribe(params => {
        const userId = params['userId'];
        console.log(userId);
      });
  }

}
Posted by: Guest on September-02-2020

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