Answers for "javascript get request"

12

Ram usage in linux

$ cat /proc/meminfo
Posted by: Guest on September-16-2020
2

how to get ram detail in linux

sudo dmidecode --type 17
Posted by: Guest on October-13-2020
37

javascript get current url

var currentUrl = window.location.href;
Posted by: Guest on July-22-2019
7

jquery ajax get

$.ajax({
    	url: "www.site.com/page",
    	success: function(data){ 
    	    $('#data').text(data);
    	},
    	error: function(){
    		alert("There was an error.");
    	}
    });
Posted by: Guest on March-28-2020
8

javascript send post request

let data = {element: "barium"};

fetch("/post/data/here", {
  method: "POST", 
  body: JSON.stringify(data)
}).then(res => {
  console.log("Request complete! response:", res);
});


// If you are as lazy as me (or just prefer a shortcut/helper):

window.post = function(url, data) {
  return fetch(url, {method: "POST", body: JSON.stringify(data)});
}

// ...

post("post/data/here", {element: "osmium"});
Posted by: Guest on March-04-2020
2

create http request javascript

const Http = new XMLHttpRequest();
const url='https://jsonplaceholder.typicode.com/posts';
Http.open("GET", url);
Http.send();

Http.onreadystatechange = (e) => {
  console.log(Http.responseText)
}
Posted by: Guest on September-14-2020
2

GET req with js

function httpGet(theUrl) {
    var xmlHttp = new XMLHttpRequest();
    xmlHttp.open( "GET", theUrl, false ); // false for synchronous request
    xmlHttp.send( null );
    return xmlHttp.responseText;
}
Posted by: Guest on August-04-2020
3

javascript http request

// Use these functions:

function _GET_REQUEST(url, response) {
  var xhttp;
  if (window.XMLHttpRequest) {
    xhttp = new XMLHttpRequest();
  } else {
    xhttp = new ActiveXObject("Microsoft.XMLHTTP");
  }

  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      response(this.responseText);
    }
  };

  xhttp.open("GET", url, true);
  xhttp.send();
}

function _POST_REQUEST(url, params, response) {
  var xhttp;
  if (window.XMLHttpRequest) {
    xhttp = new XMLHttpRequest();
  } else {
    xhttp = new ActiveXObject("Microsoft.XMLHTTP");
  }

  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      response(this.responseText);
    }
  };

  xhttp.open("POST", url, true);
  xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
  xhttp.send(params);
}


// Use like:
_GET_REQUEST('http://url.com', (response) => {
	// Do something with variable response
  	console.log(response);
});
_POST_REQUEST('http://url.com', 'parameter=sometext', (response) => {
	// Do something with variable response
  	console.log(response);
});
Posted by: Guest on October-18-2020

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