Answers for "fs open file nodejs"

12

read file node

// load fs
const fs = require("fs");
// read the file
const content = fs.readFileSync("./my_file.txt");
// print it
console.log(content.toString());
Posted by: Guest on October-11-2020
3

node open file

const fs = require("fs");

// __dirname means relative to script. Use "./data.txt" if you want it relative to execution path.
fs.readFile(__dirname + "/data.txt", (error, data) => {
    if(error) {
        throw error;
    }
    console.log(data.toString());
});
Posted by: Guest on May-25-2020
2

read a file nodejs

const fs = require('fs');

fs.readFile('my-file.txt', 'utf8', function(err, data) {
    if (err) throw err;
    console.log(data);
});
Posted by: Guest on April-17-2021
1

read file in nodejs using fs

let myFile = "./myText.txt";
const fs = require("fs");
		
app.all('/test', async (req, res) => {
	try {
		const readData = fs.readFileSync(myFile, 'utf8');
		if (readData) {
			res.send(readData)
		}
	} catch (error) {
		res.send("something is wrong", error)
	}
})
Posted by: Guest on January-07-2021
5

fs.readfile

fs.readFile('filename', function read(err, data) {
    if (err) {
        throw err;
    }
    var content = data;
  
    console.log(content);  
   
});
Posted by: Guest on April-21-2020
0

nodejs open file

fs = require('fs')
fs.readFile('/etc/hosts', 'utf8', function (err,data) {
  if (err) {
    return console.log(err);
  }
  console.log(data);
});
Posted by: Guest on December-05-2020

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