Answers for "javascript fetch url"

Javascript

js fetch 'post' json

//Obj of data to send in future like a dummyDb
const data = { username: 'example' };

//POST request with body equal on data in JSON format
fetch('https://example.com/profile', {
  method: 'POST',
  headers: {
    'Content-Type': 'application/json',
  },
  body: JSON.stringify(data),
})
.then((response) => response.json())
//Then with the data from the response in JSON...
.then((data) => {
  console.log('Success:', data);
})
//Then with the error genereted...
.catch((error) => {
  console.error('Error:', error);
});

//																		Yeah

Posted by: Guest on March-28-2020

Source

javascript fetch json

fetch('./yourjson.json')
  .then((response) => response.json())
  .then((data) => {
  	console.log(data);
  })

Posted by: Guest on December-07-2020

fetch url in javascript

fetch('https://api.github.com/users/kipngetich33')
  .then(response => response.json())
  .then(formatedResponse =>  console.log(formatedResponse))
//NB please replace url with your own

Posted by: Guest on June-30-2021

fetch api javascript

fetch('https://apiYouWantToFetch.com/players') // returns a promise
  .then(response => response.json()) // converting promise to JSON
  .then(players => console.log(players)) // console.log to view the response

Posted by: Guest on September-01-2020

fetch html from url

fetch('/about').then(function (response) {
	// The API call was successful!
	return response.text();
}).then(function (html) {

	// Convert the HTML string into a document object
	var parser = new DOMParser();
	var doc = parser.parseFromString(html, 'text/html');

	// Get the image file
	var img = doc.querySelector('img');
	console.log(img);

}).catch(function (err) {
	// There was an error
	console.warn('Something went wrong.', err);
});

Posted by: Guest on June-30-2020

Source

fetch api map

const GetData = [];
  useEffect(() => {
    fetch(API_URL)
      .then((res) => res.json())
      .then((data) => {
        GetModesData.push(...data);
        setDataState(GetData.map((d) => d.modeName));
      });
  }, []);

Posted by: Guest on June-17-2020

Source

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