Answers for "php json_decode in js"

json_decode jquery

var obj = jQuery.parseJSON( '{ "name": "John" }' );
alert( obj.name === "John" );

Posted by: Guest on December-22-2020

php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Posted by: Guest on July-01-2019

$value = '{"Name" : "Tamer"}';

json_decode($value);

Posted by: Guest on April-29-2021

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