filter array with unique objects javascript
const array =
[
{ "name": "Joe", "age": 17 },
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
]
const key = 'age';
const arrayUniqueByKey = [...new Map(array.map(item =>
[item[key], item])).values()];
console.log(arrayUniqueByKey);
/*OUTPUT
[
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
]
*/
// Note: this will pick the last duplicated item in the list.get unique values from array of objects javascript
const data = [
{ group: 'A', name: 'SD' },
{ group: 'B', name: 'FI' },
{ group: 'A', name: 'MM' },
{ group: 'B', name: 'CO'}
];
const unique = [...new Set(data.map(item => item.group))]; // [ 'A', 'B']javascript map return array with distinc values
//ES6
let array = [
{ "name": "Joe", "age": 17 },
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
];
array.map(item => item.age)
.filter((value, index, self) => self.indexOf(value) === index)
> [17, 35]javascript get unique values from key
const unique = [...new Set(array.map(item => item.age))];javascript get unique elements in array
function toUniqueArray(a){
var newArr = [];
for (var i = 0; i < a.length; i++) {
if (newArr.indexOf(a[i]) === -1) {
newArr.push(a[i]);
}
}
return newArr;
}
var colors = ["red","red","green","green","green"];
var colorsUnique=toUniqueArray(colors); // ["red","green"]create unique set of array of objects
function unique(array, propertyName) {
return array.filter((e, i) => array.findIndex(a => a[propertyName] === e[propertyName]) === i);
}Copyright © 2021 Codeinu
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