Answers for "json_decode object"

json_decode jquery

var obj = jQuery.parseJSON( '{ "name": "John" }' );
alert( obj.name === "John" );

Posted by: Guest on December-22-2020

php json_decode

$personJSON = '{"name":"Johny Carson","title":"CTO"}';

$person = json_decode($personJSON);

echo $person->name; // Johny Carson

Posted by: Guest on July-01-2019

php decode json object

<?php

$json = '{"firstName":"Peter","lastName:":"Silva","age":23}';

$personInfo = json_decode(json);

echo $personInfo->age;

?>

Posted by: Guest on October-22-2020

$value = '{"Name" : "Tamer"}';

json_decode($value);

Posted by: Guest on April-29-2021

Code answers related to "json_decode object"