Answers for "js time difference between two dates"

Javascript

javascript difference between two dates

const date1 = new Date('7/13/2010');
const date2 = new Date('12/15/2010');
console.log(getDifferenceInDays(date1, date2));
console.log(getDifferenceInHours(date1, date2));
console.log(getDifferenceInMinutes(date1, date2));
console.log(getDifferenceInSeconds(date1, date2));

function getDifferenceInDays(date1, date2) {
  const diffInMs = Math.abs(date2 - date1);
  return diffInMs / (1000 * 60 * 60 * 24);
}

function getDifferenceInHours(date1, date2) {
  const diffInMs = Math.abs(date2 - date1);
  return diffInMs / (1000 * 60 * 60);
}

function getDifferenceInMinutes(date1, date2) {
  const diffInMs = Math.abs(date2 - date1);
  return diffInMs / (1000 * 60);
}

function getDifferenceInSeconds(date1, date2) {
  const diffInMs = Math.abs(date2 - date1);
  return diffInMs / 1000;
}

Posted by: Guest on January-21-2020

Source

javascript difference between two dates in days

const diffDays = (date, otherDate) => Math.ceil(Math.abs(date - otherDate) / (1000 * 60 * 60 * 24));

// Example
diffDays(new Date('2014-12-19'), new Date('2020-01-01'));   // 1839

Posted by: Guest on July-03-2020

Source

javascript difference between two dates

var date1 = new Date();    
 var date2 = new Date("2025/07/30 21:59:00");
  
showDiff(date1,date2);

function showDiff(date1, date2){

    var diff = (date2 - date1)/1000;
    diff = Math.abs(Math.floor(diff));

    var days = Math.floor(diff/(24*60*60));
    var leftSec = diff - days * 24*60*60;

    var hrs = Math.floor(leftSec/(60*60));
    var leftSec = leftSec - hrs * 60*60;

    var min = Math.floor(leftSec/(60));
    var leftSec = leftSec - min * 60;
	console.info("You have " + days + " days " + hrs + " hours " + min + " minutes and " + leftSec + " seconds");
   
    return {
        d: days,
        h: hrs,
        i: min,
        s: leftSec
    };
}

Posted by: Guest on April-01-2021

check a date is between two dates in javascript

const dateCheck = (from, to, check) => {
    let fDate,lDate,cDate;
    fDate = Date.parse(from);
    lDate = Date.parse(to);
    cDate = Date.parse(check);
    if((cDate <= lDate && cDate >= fDate))  return true
    return false;
}
dateCheck("02/05/2021","02/09/2021","02/07/2021")

Posted by: Guest on October-20-2021

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