Answers for "calculate days between two dates javascript"

5

How do I get the number of days between two dates in JavaScript

let today = new Date().toISOString().slice(0, 10)

const startDate  = '2021-04-15';
const endDate    = today;

const diffInMs   = new Date(endDate) - new Date(startDate)
const diffInDays = diffInMs / (1000 * 60 * 60 * 24);


alert( diffInDays  );
Posted by: Guest on August-07-2021
0

javascript calculate days between dates

function calculateDaysBetweenDates(date1, date2) {
  var oneDay = 24 * 60 * 60 * 1000;
  var date1InMillis = date1.getTime();
  var date2InMillis = date2.getTime();
  var days = Math.round(Math.abs(date2InMillis - date1InMillis) / oneDay);
  return days;
}
Posted by: Guest on July-01-2021
2

javascript difference between two dates in days

const diffDays = (date, otherDate) => Math.ceil(Math.abs(date - otherDate) / (1000 * 60 * 60 * 24));

// Example
diffDays(new Date('2014-12-19'), new Date('2020-01-01'));   // 1839
Posted by: Guest on July-03-2020
1

how to calculate the number of days between two dates in javascript

function javascript (date1, date2) {
   let oned = 24 * 60 * 60 * 1000;
   return Math.ceil((date2 - date1) / oned);
}

function javascript(date1, date2) {
	return new Date(date2 - date1).getDate() - 1
}

function javascript(date1, date2) {
  return Math.ceil((date2 - date1) / 8.64e7);
}
Posted by: Guest on June-23-2020
-1

js get difference in days

const date1 = new Date('19/1/2021');
const date2 = new Date('20/1/2021');
const diffTime = Math.abs(date2 - date1);
const diffDays = Math.ceil(diffTime / (1000 * 60 * 60 * 24)); 
console.log(diffTime + " milliseconds");
console.log(diffDays + " days");
Posted by: Guest on January-20-2021
2

javascript difference between two dates in days

/* difference between date1 and date2 in days (date2 - date1) */
/* date1 and date 2 are already javascript date objects */
function dateDifference(date2, date1) {
    const _MS_PER_DAY = 1000 * 60 * 60 * 24;

    // Discard the time and time-zone information.
    const utc1 = Date.UTC(date1.getFullYear(), date1.getMonth(), date1.getDate());
    const utc2 = Date.UTC(date2.getFullYear(), date2.getMonth(), date2.getDate());

    return Math.floor((utc2 - utc1) / _MS_PER_DAY);
}
Posted by: Guest on July-16-2020

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