Answers for "js extract query params"

7

js get query param

const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Posted by: Guest on June-25-2020
4

javascript get query parameter

function getUrlParameter(name) {
    name = name.replace(/[\[]/, '\\[').replace(/[\]]/, '\\]');
    var regex = new RegExp('[\\?&]' + name + '=([^&#]*)');
    var results = regex.exec(location.search);
    return results === null ? '' : decodeURIComponent(results[1].replace(/\+/g, ' '));
};
Posted by: Guest on June-27-2019
0

javascript get params from query strinG

let parameters = 'www.goole.com?code=1232';
// const value = parameters.get('emailVf');
var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))

output : {code:1232}:



)=================================================
IF YOU WANT 	TO USE URL FROM BROWSER THEN USE 
==========================
const parameters = window.location.search;

var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))

___________________________________________
ANOTHER WAY IS ======================[[
  
const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Posted by: Guest on June-10-2021

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