Answers for "how to get query params from url"

10

javascript read query parameters

// example url: https://mydomain.com/?fname=johnny&lname=depp
const queryString = window.location.search;
console.log(queryString);
// ?fname=johnny&lname=depp

const urlParams = new URLSearchParams(queryString);

const firstName = urlParams.get('fname');
console.log(firstName);
// johnny

const lastName = urlParams.get('lname');
console.log(lastName);
// depp
Posted by: Guest on May-04-2020
7

js get query param

const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Posted by: Guest on June-25-2020
1

get url query params js

const urlParams = new URLSearchParams(window.location.search);
const myParam = urlParams.get('myParam');
Posted by: Guest on July-26-2020
0

get query params from url javascript

const queryString = window.location.href;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Posted by: Guest on August-20-2021
0

javascript get params from query strinG

let parameters = 'www.goole.com?code=1232';
// const value = parameters.get('emailVf');
var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))

output : {code:1232}:



)=================================================
IF YOU WANT 	TO USE URL FROM BROWSER THEN USE 
==========================
const parameters = window.location.search;

var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))

___________________________________________
ANOTHER WAY IS ======================[[
  
const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Posted by: Guest on June-10-2021

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