Answers for "get query param js"

7

js get query param

const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Posted by: Guest on June-25-2020
3

get query param javascript

const urlParams = new URLSearchParams(window.location.search);
const myParam = urlParams.get('myParam');
Posted by: Guest on November-18-2020
2

javascript reading query parameter

// example url: https://mydomain.com/?fname=johnny&lname=depp
const urlParams = new URLSearchParams(window.location.search);
const firstName = urlParams.get('fname'); // johnny
Posted by: Guest on September-18-2020
4

javascript get query parameter

function getUrlParameter(name) {
    name = name.replace(/[\[]/, '\\[').replace(/[\]]/, '\\]');
    var regex = new RegExp('[\\?&]' + name + '=([^&#]*)');
    var results = regex.exec(location.search);
    return results === null ? '' : decodeURIComponent(results[1].replace(/\+/g, ' '));
};
Posted by: Guest on June-27-2019
1

Get the get query in javascript

function getParameterByName(name, url = window.location.href) {
    name = name.replace(/[\[\]]/g, '\\$&');
    var regex = new RegExp('[?&]' + name + '(=([^&#]*)|&|#|$)'),
        results = regex.exec(url);
    if (!results) return null;
    if (!results[2]) return '';
    return decodeURIComponent(results[2].replace(/\+/g, ' '));
}

// query string: ?foo=lorem&bar=&baz
var foo = getParameterByName('foo'); // "lorem"
var bar = getParameterByName('bar'); // "" (present with empty value)
var baz = getParameterByName('baz'); // "" (present with no value)
var qux = getParameterByName('qux'); // null (absent)
Posted by: Guest on September-13-2021
0

javascript get params from query strinG

let parameters = 'www.goole.com?code=1232';
// const value = parameters.get('emailVf');
var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))

output : {code:1232}:



)=================================================
IF YOU WANT 	TO USE URL FROM BROWSER THEN USE 
==========================
const parameters = window.location.search;

var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))

___________________________________________
ANOTHER WAY IS ======================[[
  
const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Posted by: Guest on June-10-2021

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