javascript reverse a string
function reverseString(s){
return s.split("").reverse().join("");
}
reverseString("Hello");//"olleH"javascript reverse a string
function reverseString(s){
return s.split("").reverse().join("");
}
reverseString("Hello");//"olleH"reverse a string javascript
//with built-in method
let string = "We are going to reverse a string with built-in method.";
let reversed = string.split("").reverse().join("");
console.log(reversed);
//with the for loop
let string = "We are going to reverse a string with the for loop.";
function reverse (string){
let reversed = "";
for(let char of string){
reversed = char + reversed;
}
return reversed;
}
console.log(reverse(string));
//with the spread operator
let string = "We are going to reverse a string with the spread operator.";
let reversed = [...string].reverse().join("");
console.log(reversed);
//with iteration
let string = "We are going to reverse a string with iteration.";
function reverse(string) {
for (var reversed = "", i = string.length - 1; i >= 0; i--) {
reversed += string[i];
}
return reversed;
console.log(reverse(string));how to reverse a string in javascript without using reverse method
function reverseString(str) {
return str.split("").reverse().join("");
}
reverseString("hello");how to reverse a string in javascript without using reverse method
function reverseString(str) {
var newString = "";
for (var i = str.length - 1; i >= 0; i--) {
newString += str[i];
}
return newString;
}
reverseString('hello');how to reverse a string in javascript without using reverse method
function reverseString(str) {
if (str === "")
return "";
else
return reverseString(str.substr(1)) + str.charAt(0);
}
reverseString("hello");how to reverse a string in javascript without using reverse method
function reverseString(str) {
if (str === "") // This is the terminal case that will end the recursion
return "";
else
return reverseString(str.substr(1)) + str.charAt(0);
/*
First Part of the recursion method
You need to remember that you won’t have just one call, you’ll have several nested calls
Each call: str === "?" reverseString(str.subst(1)) + str.charAt(0)
1st call – reverseString("Hello") will return reverseString("ello") + "h"
2nd call – reverseString("ello") will return reverseString("llo") + "e"
3rd call – reverseString("llo") will return reverseString("lo") + "l"
4th call – reverseString("lo") will return reverseString("o") + "l"
5th call – reverseString("o") will return reverseString("") + "o"
Second part of the recursion method
The method hits the if condition and the most highly nested call returns immediately
5th call will return reverseString("") + "o" = "o"
4th call will return reverseString("o") + "l" = "o" + "l"
3rd call will return reverseString("lo") + "l" = "o" + "l" + "l"
2nd call will return reverserString("llo") + "e" = "o" + "l" + "l" + "e"
1st call will return reverserString("ello") + "h" = "o" + "l" + "l" + "e" + "h"
*/
}
reverseString("hello");Copyright © 2021 Codeinu
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