js sum of array
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
// Output: 10js sum of array
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
// Output: 10add all elements in array javascript
console.log(
[1, 2, 3, 4].reduce((a, b) => a + b, 0)
)
console.log(
[].reduce((a, b) => a + b, 0)
)sum of all numbers in an array javascript
const arrSum = arr => arr.reduce((a,b) => a + b, 0)sum the all values from an array
var numbers = [3, 5, 7, 2];
var sum = numbers.reduce((x, y) => x + y);
console.log(sum); // returns 17
// other way
x = sumAll(1, 123, 500, 115, 44, 88);
function sumAll() {
var i;
var sum = 0;
for (i = 0; i < arguments.length; i++) {
sum += arguments[i];
}
return sum;
}sum of all elements in array javascript
arrSum = function(arr){ return arr.reduce(function(a,b){ return a + b }, 0);}Copyright © 2021 Codeinu
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