greater number in arraya jd
var array = [3 , 6, 2, 56, 32, 5, 89, 32];
var largest= 0;
for (i=0; i<=largest;i++){
if (array[i]>largest) {
var largest=array[i];
}
}
console.log(largest);greater number in arraya jd
var array = [3 , 6, 2, 56, 32, 5, 89, 32];
var largest= 0;
for (i=0; i<=largest;i++){
if (array[i]>largest) {
var largest=array[i];
}
}
console.log(largest);get highest value from array javascript
//For Values
var arr =[1,10,3]
var min = Math.min.apply(null, arr),
max = Math.max.apply(null, arr);
//For Objects
var arr = [{a: 1},{a: 10},{a: 3}]
var values = arr.map(val => val.a);
var max = Math.max.apply(null, values);
console.log(max)find biggest number in javascript array
var peopleData = [
{ name: "Paul", height: 180, age: 21 },
{ name: "Johnny", height: 198, age: 43 },
{ name: "Brad", height: 172, age: 49 },
{ name: "Dwayne", height: 166, age: 15 }
];
//Find biggest height number
var maxHeight = 0;
for (var i = 0; i < heights.length; i++) {
if (peopleData[i].height > maxHeight) {
maxHeight = peopleData[i].height;
//if you console.log(maxHeight); you should get 198
}
}get largest number in array javascript
const array1 = [1, 3, 2];
Math.max(...array1);
// expected output: 3javascript get array min and max
//get min/max value of arrays
function getArrayMax(array){
return Math.max.apply(null, array);
}
function getArrayMin(array){
return Math.min.apply(null, array);
}
var ages=[11, 54, 32, 92];
var maxAge=getArrayMax(ages); //92
var minAge=getArrayMin(ages); //11find highest number in array javascript
function findHighestNumber(nums) {
let inputs = nums.filter((val, i) => nums.indexOf(val) === i)
let max = Math.max(...nums);
let min = Math.min(...nums);
return max + (-min);
}
console.log(difference([1, 7, 18, -1, -2, 9]));Copyright © 2021 Codeinu
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