javascript default parameters object destructuring
You can use "defaults" in destructuring as well:
(function test({a = "foo", b = "bar"} = {}) {
console.log(a + " " + b);
})();
This is not restricted to function parameters,
but works in every destructuring expression.javascript function destructuring
function f() {
return [1, 2];
}
let a, b;
[a, b] = f();
console.log(a); // 1
console.log(b); // 2object destructuring default value
let a, b;
[a=5, b=7] = [1];
console.log(a); // 1
console.log(b); // 7array destructuring in javascript
const array = ['ismail', 'sulman'];
// array destructuring
const [firstElement, secondElement] = array;
console.log(firstElement, secondElement);
const secondArray = ['ismail', 'naeem', 'Mr', 1];
const [firstEl, secondEl, ...array1] = secondArray;
console.log(firstEl, secondEl, array1);js object destructuring
const { [propName]: identifier } = expression;js object destructuring with defaults
// Taken from top stack overflow answer
const { dogName = 'snickers' } = { dogName: undefined }
console.log(dogName) // what will it be? 'snickers'!
const { dogName = 'snickers' } = { dogName: null }
console.log(dogName) // what will it be? null!
const { dogName = 'snickers' } = { dogName: false }
console.log(dogName) // what will it be? false!
const { dogName = 'snickers' } = { dogName: 0 }
console.log(dogName) // what will it be? 0!Copyright © 2021 Codeinu
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