Answers for "filter out object in array using two arguments"

1

filter out object in array using two arguments

var arr= [{id: "123", name: "Faa"},
          {id: "123", name: "Bar"},
          {id: "345", name: "Foo"},
          {id: "678", name: "FaaBar"}
         ];

var name = 'FaaBar';
var id = '678';

arr = arr.filter(function(elem) {
  //return false for the element that matches both the name and the id
  return !(elem.id == id && elem.name == name)
});
Posted by: Guest on June-25-2020
14

how the filter() function works javascript

const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];

const filter = arr.filter((number) => number > 5);
console.log(filter); // [6, 7, 8, 9]
Posted by: Guest on April-07-2020
0

filter js object array based on multiple parameters

var arr= [{id: "123", name: "Foo"},
          {id: "123", name: "Bar"},
          {id: "345", name: "Foo"},
          {id: "678", name: "FooBar"}
         ];

var name = 'Foo';
var id = '123';

arr = arr.filter(function(elem) {
  //return false for the element that matches both the name and the id
  return !(elem.id == id && elem.name == name)
});
Posted by: Guest on May-03-2021

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