Answers for "Count frequency of array elements js"

7

javascript Count the frequency of a value in an array

const countOccurrences = arr => arr.reduce((prev, curr) => (prev[curr] = ++prev[curr] || 1, prev), {});

// Examples
countOccurrences([2, 1, 3, 3, 2, 3]);               // { '1': 1, '2': 2, '3': 3 }
countOccurrences(['a', 'b', 'a', 'c', 'a', 'b']);   // { 'a': 3, 'b': 2, 'c': 1 }
Posted by: Guest on July-02-2020
1

Count frequency of array elements js

var arr = [5, 5, 5, 2, 2, 2, 2, 2, 9, 4]

const map = arr.reduce((acc, e) => acc.set(e, (acc.get(e) || 0) + 1), new Map());

console.info([...map.keys()]) // to get unique elements
console.info([...map.values()]) // to get the occurrences
console.info([...map.entries()]) // to get the pairs [element, frequency]
Posted by: Guest on August-18-2020
1

count number of times an element is occuring in an array in javascript

Array.prototype.frequencies = function() {
    var l = this.length, result = {all:[]};
    while (l--){
       result[this[l]] = result[this[l]] ? ++result[this[l]] : 1;
    }
    // all pairs (label, frequencies) to an array of arrays(2)
    for (var l in result){
       if (result.hasOwnProperty(l) && l !== 'all'){
          result.all.push([ l,result[l] ]);
       }
    }
    return result;
};

var freqs = [5, 5, 5, 2, 2, 2, 2, 2, 9, 4].frequencies();
alert(freqs[2]); //=> 5
// or
var freqs = '1,1,2,one,one,2,2,22,three,four,five,three,three,five'
             .split(',')
             .frequencies();
alert(freqs.three); //=> 3
Posted by: Guest on January-16-2020

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