sorting array from highest to lowest javascript
// Sort an array of numbers
let numbers = [5, 13, 1, 44, 32, 15, 500]
// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]
//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortsort javascript array
var points = [40, 100, 1, 5, 25, 10];
points.sort((a,b) => a-b)javascript sort
var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]
var objs = [
{name: "Peter", age: 35},
{name: "Emma", age: 21},
{name: "Jack", age: 53}
];
objs.sort(function(a, b) {
return a.age - b.age;
}); // Sort by age (lowest first)sort js
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortarr.sort()
const points = [40, 100, 1, 5, 25, 10];
points.sort(function(a, b){return a - b}); // for ascending
//another way for ascending
points.sort((a,b)=>{
if(a>b){
return 1
}else if(a<b){
return -1
}else{
return 0
}
})
points.sort(function(a, b){return b - a}); // for descending
//another way for descending
points.sort((a,b)=>{
if(a>b){
return -1
}else if(a<b){
return 1
}else{
return 0
}
})Copyright © 2021 Codeinu
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