object get property with max value javascript
var obj = {a: 1, b: 2, undefined: 1};
Object.keys(obj).reduce((a, b) => (obj[a] > obj[b]) ? a : b);
object get property with max value javascript
var obj = {a: 1, b: 2, undefined: 1};
Object.keys(obj).reduce((a, b) => (obj[a] > obj[b]) ? a : b);
max value array of object javascript
Math.max(...arr.map({ value } => value));
get object with max value javascript
let objects = [{id: 0, votes: 5}, {id: 1, votes: 3}, {id: 2, votes: 11}]
let maxObj = objects.reduce((max, obj) => (max.votes > obj.votes) ? max : obj);
/* `max` is always the object with the highest value so far.
* If `obj` has a higher value than `max`, then it becomes `max` on the next iteration.
* So here:
* | max = {id: 0, votes: 5}, obj = {id: 1, votes: 3}
* | max = {id: 0, votes: 5}, obj = {id: 2, votes: 11}
* reduced = {id: 2, votes: 11}
*/
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