Answers for "js regex test if string even or odd"

function isEven(n) {
   return n % 2 == 0;
}

function isOdd(n) {
   return Math.abs(n % 2) == 1;
}

Posted by: Guest on September-06-2020

odd or even js

for(let count =0; count<=100;count++){
 count%2==0? console.log(`${count} is even`):console.log(`${count} is odd`);
 ;
}

Posted by: Guest on June-28-2020

Code answers related to "js regex test if string even or odd"