javascript last index
var colors = ["red","blue","green"];
var green = colors[colors.length - 1]; //get last item in the arrayjavascript last index
var colors = ["red","blue","green"];
var green = colors[colors.length - 1]; //get last item in the arraylast index of javascript
var str = "Please locate where 'locate' occurs!";
var ind1 = str.indexOf("locate"); // return location of first value which founded
var ind2 = str.lastIndexOf("locate"); // return location of last value which founded
var ind3 = str.indexOf("locate", 15); // start search from location 15 and then take first value which founded
var ind4 = str.search("locate");
//The search() method cannot take a second start position argument.
//The indexOf() method cannot take powerful search values (regular expressions).
document.write("<br>" + "Length of string:", len);
document.write("<br>" + "indexOf:", ind1);
document.write("<br>" + "index of last:", ind2);
document.write("<br>" + "indexOf with start point:", ind3);
document.write("<br>" + "search:", ind4);js last index of
const str = "Users/Edit/12345";
let idx = str.lastIndexOf("/"); // returns 10
idx = str.lastIndexOf("x"); // returns -1
idx = str.lastIndexOf("Edit") // returns 6
idx = str.lastIndexOf("edit") // returns -1 -- case sensitive
// add "from" parameter
// the search happens backwards, starting at the provided from parameter
idx = str.lastIndexOf("s"); // returns 4
idx = str.lastIndexOf("s", 3); // returns 1lastindexof javascript
string.lastIndexOf(searchValue[, fromIndex])lastindexof() javascript
'canal'.lastIndexOf('a'); // retorna 3
'canal'.lastIndexOf('a', 2); // retorna 1
'canal'.lastIndexOf('a', 0); // retorna -1
'canal'.lastIndexOf('x'); // retorna -1
'canal'.lastIndexOf('c', -5); // retorna 0
'canal'.lastIndexOf('c', 0); // retorna 0
'canal'.lastIndexOf(''); // retorna 5
'canal'.lastIndexOf('', 2); // retorna 2last index of array js
array.lastIndexOf(searchElement[, fromIndex]);Copyright © 2021 Codeinu
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