Answers for "array.filter in js"

79

filter javascript array

var words = ['spray', 'limit', 'elite', 'exuberant', 'destruction', 'present'];

const result = words.filter(word => word.length > 6);

console.log(result);
Posted by: Guest on November-11-2019
31

.filter js

const words = ['spray', 'limit', 'elite', 'exuberant', 'destruction', 'present'];

const result = words.filter(word => word.length > 6);

console.log(result);
// expected output: Array ["exuberant", "destruction", "present"]
Posted by: Guest on May-08-2020
8

filter javascript

const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];

const filter = arr.filter((number) => number > 5);
console.log(filter); // [6, 7, 8, 9]

or 

const words = ['spray', 'limit', 'elite', 'exuberant', 'destruction', 'present'];

const result = words.filter(word => word.length > 6);

console.log(result);
// expected output: Array ["exuberant", "destruction", "present"]
Posted by: Guest on August-25-2020
17

javascript array filter

var numbers = [1, 3, 6, 8, 11];

var lucky = numbers.filter(function(number) {
  return number > 7;
});

// [ 8, 11 ]
Posted by: Guest on November-17-2019
5

filter in js

const filterThisArray = ["a","b","c","d","e"] 
console.log(filterThisArray) // Array(5) [ "a","b","c","d","e" ]

const filteredThatArray = filterThisArray.filter((item) => item!=="e")
console.log(filteredThatArray) // Array(4) [ "a","b","c","d" ]
Posted by: Guest on August-03-2020
3

array.filter in js

var numbers = [1, 3, 6, 8, 11];

var lucky = numbers.filter(function(number) {
  return number > 7;
});
Posted by: Guest on June-11-2020

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