xml to json python
Soviut's advice for lxml objectify is good. With a specially subclassed simplejson, you can turn an lxml objectify result into json.
import simplejson as json
import lxml
class objectJSONEncoder(json.JSONEncoder):
"""A specialized JSON encoder that can handle simple lxml objectify types
>>> from lxml import objectify
>>> obj = objectify.fromstring("<Book><price>1.50</price><author>W. Shakespeare</author></Book>")
>>> objectJSONEncoder().encode(obj)
'{"price": 1.5, "author": "W. Shakespeare"}'
"""
def default(self,o):
if isinstance(o, lxml.objectify.IntElement):
return int(o)
if isinstance(o, lxml.objectify.NumberElement) or isinstance(o, lxml.objectify.FloatElement):
return float(o)
if isinstance(o, lxml.objectify.ObjectifiedDataElement):
return str(o)
if hasattr(o, '__dict__'):
#For objects with a __dict__, return the encoding of the __dict__
return o.__dict__
return json.JSONEncoder.default(self, o)
See the docstring for example of usage, essentially you pass the result of lxml objectify to the encode method of an instance of objectJSONEncoder
Note that Koen's point is very valid here, the solution above only works for simply nested xml and doesn't include the name of root elements. This could be fixed.
I've included this class in a gist here: http://gist.github.com/345559
