Answers for "json_encode()"

11

why json_encode or json_decode returns false

<?php
// A valid json string
$json[] = '{"Organization": "PHP Documentation Team"}';

// An invalid json string which will cause an syntax 
// error, in this case we used ' instead of " for quotation
$json[] = "{'Organization': 'PHP Documentation Team'}";


foreach ($json as $string) {
    echo 'Decoding: ' . $string;
    json_decode($string);

    switch (json_last_error()) {
        case JSON_ERROR_NONE:
            echo ' - No errors';
        break;
        case JSON_ERROR_DEPTH:
            echo ' - Maximum stack depth exceeded';
        break;
        case JSON_ERROR_STATE_MISMATCH:
            echo ' - Underflow or the modes mismatch';
        break;
        case JSON_ERROR_CTRL_CHAR:
            echo ' - Unexpected control character found';
        break;
        case JSON_ERROR_SYNTAX:
            echo ' - Syntax error, malformed JSON';
        break;
        case JSON_ERROR_UTF8:
            echo ' - Malformed UTF-8 characters, possibly incorrectly encoded';
        break;
        default:
            echo ' - Unknown error';
        break;
    }

    echo PHP_EOL;
}
?>
Posted by: Guest on March-26-2021
8

php json_encode

$person = array( 
    "name" => "Johny Carson", 
    "title" => "CTO"
); 
$personJSON=json_encode($person);//returns JSON string
Posted by: Guest on July-01-2019
0

json_encode()

json_encode(['name' => 'Jake', 'country' => 'Philippines'])
Posted by: Guest on February-25-2021
0

json_encode()

<?php
$age = array("Peter"=>35, "Ben"=>37, "Joe"=>43);

  
echo json_encode($age);
?>
Posted by: Guest on March-16-2021

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