Answers for "javascript promise.all"

7

javascript promise all

var p1 = Promise.resolve(3);
var p2 = 1337;
var p3 = new Promise((resolve, reject) => {
  setTimeout(resolve, 100, "foo");
}); 

Promise.all([p1, p2, p3]).then(values => { 
  console.log(values); // [3, 1337, "foo"] 
});
Posted by: Guest on February-26-2020
3

javascript promise.all

try {
    const [res1, res2, res3] = await Promise.all([
      Promise1,
      Promise2,
      Promise3,
    ]);
  } catch (err) {
    console.error(err);
  }
Posted by: Guest on February-21-2021
5

promise all

Promise.all([Promise1, Promise2, Promise3])
 .then(result) => {
   console.log(result)
 })
 .catch(error => console.log(`Error in promises ${error}`))
Posted by: Guest on June-01-2020
5

Promise.all

const promise1 = Promise.resolve(3);
const promise2 = 42;
const promise3 = new Promise(function(resolve, reject) {
  setTimeout(resolve, 100, 'foo');
});

Promise.all([promise1, promise2, promise3]).then(function(values) {
  console.log(values);
});
// expected output: Array [3, 42, "foo"]
Posted by: Guest on March-23-2020
2

javascript promise.all

// PARALLEL PROMISES
async function fetchMoviesAndCategories() {
  const [moviesResponse, categoriesResponse] = await Promise.all([
    fetch('/movies'),
    fetch('/categories')
  ]);

  const movies = await moviesResponse.json();
  const categories = await categoriesResponse.json();

  return [movies, categories];
}
Posted by: Guest on February-21-2021
1

promise.all

const durations = [1000, 2000, 3000]

promises = durations.map((duration) => {
  return timeOut(duration).catch(e => e) // Handling the error for each promise.
})

Promise.all(promises)
  .then(response => console.log(response)) // ["Completed in 1000", "Rejected in 2000", "Completed in 3000"]
  .catch(error => console.log(`Error in executing ${error}`))
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Posted by: Guest on May-27-2020

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