javascript last index
var colors = ["red","blue","green"];
var green = colors[colors.length - 1]; //get last item in the array
javascript last index
var colors = ["red","blue","green"];
var green = colors[colors.length - 1]; //get last item in the array
last index of javascript
var str = "Please locate where 'locate' occurs!";
var ind1 = str.indexOf("locate"); // return location of first value which founded
var ind2 = str.lastIndexOf("locate"); // return location of last value which founded
var ind3 = str.indexOf("locate", 15); // start search from location 15 and then take first value which founded
var ind4 = str.search("locate");
//The search() method cannot take a second start position argument.
//The indexOf() method cannot take powerful search values (regular expressions).
document.write("<br>" + "Length of string:", len);
document.write("<br>" + "indexOf:", ind1);
document.write("<br>" + "index of last:", ind2);
document.write("<br>" + "indexOf with start point:", ind3);
document.write("<br>" + "search:", ind4);
js last index of
const str = "Users/Edit/12345";
let idx = str.lastIndexOf("/"); // returns 10
idx = str.lastIndexOf("x"); // returns -1
idx = str.lastIndexOf("Edit") // returns 6
idx = str.lastIndexOf("edit") // returns -1 -- case sensitive
// add "from" parameter
// the search happens backwards, starting at the provided from parameter
idx = str.lastIndexOf("s"); // returns 4
idx = str.lastIndexOf("s", 3); // returns 1
typescript last index of array
var items: String[] = ["tom", "jeff", "sam"];
alert(items[items.length-1])
last index of array js
array.lastIndexOf(searchElement[, fromIndex]);
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