sum of two numbers in javascript
function sumArray(a, b) {
var c = [];
for (var i = 0; i < Math.max(a.length, b.length); i++) {
c.push((a[i] || 0) + (b[i] || 0));
}
return c;
}sum of two numbers in javascript
function sumArray(a, b) {
var c = [];
for (var i = 0; i < Math.max(a.length, b.length); i++) {
c.push((a[i] || 0) + (b[i] || 0));
}
return c;
}two sum javascript solution
var twoSum = function(nums, target) {
const indicies = {}
for (let i = 0; i < nums.length; i++) {
const num = nums[i]
if (indicies[target - num] != null) {
return [indicies[target - num], i]
}
indicies[num] = i
}
};sum of two array in javascript
function sumArrays(...arrays) {
const n = arrays.reduce((max, xs) => Math.max(max, xs.length), 0);
const result = Array.from({ length: n });
return result.map((_, i) => arrays.map(xs => xs[i] || 0).reduce((sum, x) => sum + x, 0));
}
console.log(...sumArrays([0, 1, 2], [1, 2, 3, 4], [1, 2])); // 2 5 5 4two sum javascript
var twoSum = function(nums, target) {
//hash table
var hash = {};
for(let i=0; i<=nums.length; i++){
//current number
var currentNumber = nums[i];
//difference in the target and current number
var requiredNumber = target - currentNumber;
// find the difference number from hashTable
const index2 = hash[requiredNumber];
// if number found, return index
// it will return undefined if not found
if(index2 != undefined) {
return [index2, i]
} else {
// if not number found, we add the number into the hashTable
hash[currentNumber] = i;
}
}
};Copyright © 2021 Codeinu
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