array spread operator in javascript
let arr1 = ['A', 'B', 'C'];
let arr2 = ['X', 'Y', 'Z'];
let result = [...arr1, ...arr2];
console.log(result); // ['A', 'B', 'C', 'X', 'Y', 'Z']
// spread elements of the array instead of taking the array as a wholejavascript spread operator
function sum(x, y, z) {
return x + y + z;
}
const numbers = [1, 2, 3];
console.log(sum(...numbers));
// expected output: 6
console.log(sum.apply(null, numbers));
// expected output: 6spread operator javascript
const parts = ['shoulders', 'knees'];
const lyrics = ['head', ...parts, 'and', 'toes'];
// ["head", "shoulders", "knees", "and", "toes"]spread operator
function sum(x, y, z) {
return x + y + z;
}
const numbers = [1, 2, 3];
console.log(sum(...numbers));
// expected output: 6
console.log(sum.apply(null, numbers));
// expected output: 6spread operator
function sum(x, y, z) {
return x + y + z;
}
const numbers = [1, 2, 3];
console.log(sum(...numbers));
// expected output: 6
// This will add each item in number arrray in sum method.
console.log(sum.apply(null, numbers));
// expected output: 6spread operator
let obj1 = { foo: 'bar', x: 42 };
let obj2 = { foo: 'baz', y: 13 };
let clonedObj = { ...obj1 };
// Object { foo: "bar", x: 42 }
let mergedObj = { ...obj1, ...obj2 };
// Object { foo: "baz", x: 42, y: 13 }Copyright © 2021 Codeinu
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