Answers for "Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };"

10

javascript get array min and max

//get min/max value of arrays
function getArrayMax(array){
   return Math.max.apply(null, array);
}
function getArrayMin(array){
   return Math.min.apply(null, array);
}
var ages=[11, 54, 32, 92];
var maxAge=getArrayMax(ages); //92
var minAge=getArrayMin(ages); //11
Posted by: Guest on July-31-2019
1

find max value in javascript

x = findMax(1, 123, 500, 115, 44, 88);

function findMax() {
  var i;
  var max = -Infinity;
  for (i = 0; i < arguments.length; i++) {
    if (arguments[i] > max) {
      max = arguments[i];
    }
  }
  return max;
}
Posted by: Guest on November-25-2020
0

Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

//get min/max value of arrays
function getArrayMax(array){
   return Math.max.apply(null, array);
}
function getArrayMin(array){
   return Math.min.apply(null, array);
}
var ages=[11, 54, 32, 92];
var maxAge=getArrayMax(ages); //92
var minAge=getArrayMin(ages); //11
Posted by: Guest on December-22-2020
0

Number.prototype.between = function(a, b) { var min = Math.min.apply(Math, [a, b]), max = Math.max.apply(Math, [a, b]); return this > min && this < max; };

x = findMax(1, 123, 500, 115, 44, 88);

function findMax() {
  var i;
  var max = -Infinity;
  for (i = 0; i < arguments.length; i++) {
    if (arguments[i] > max) {
      max = arguments[i];
    }
  }
  return max;
}
Posted by: Guest on December-22-2020
0

javascript set value to the largest value in an array

//get min/max value of arrays
function getArrayMax(array){
   return Math.max.apply(null, array);
Posted by: Guest on November-06-2020

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