how to flatten array with reduce in javascript
let flattened = [[0, 1], [2, 3], [4, 5]].reduce(
function(accumulator, currentValue) {
return accumulator.concat(currentValue)
},
[]
)
// flattened is [0, 1, 2, 3, 4, 5]how to flatten array with reduce in javascript
let flattened = [[0, 1], [2, 3], [4, 5]].reduce(
function(accumulator, currentValue) {
return accumulator.concat(currentValue)
},
[]
)
// flattened is [0, 1, 2, 3, 4, 5]javascript reduce array of objects
var objs = [
{name: "Peter", age: 35},
{name: "John", age: 27},
{name: "Jake", age: 28}
];
objs.reduce(function(accumulator, currentValue) {
return accumulator + currentValue.age;
}, 0); // 35 + 27 + 28 = 90javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82javascript sum array values
function getArraySum(a){
var total=0;
for(var i in a) {
total += a[i];
}
return total;
}
var payChecks = [123,155,134, 205, 105];
var weeklyPay= getArraySum(payChecks); //sums up to 722javascript reduce sum
let nums = [1, 2, 3];
nums.reduce((curr, next) => curr + next);reduce method javascript
// Reduce() method executes a callback function that is passed in
// on each element of the array, resulting in single output value.
const array1 = [1, 2, 3, 4];
const callback = (accumulator, currentValue) => accumulator + currentValue;
// 1 + 2 + 3 + 4
console.log(array1.reduce(callback));
// expected output: 10
// 5 + 1 + 2 + 3 + 4
console.log(array1.reduce(callback, 5));
// expected output: 15 because the initial value is 5.
// This is how Reduce works.
// This is a myReduce method which takes a callback and an optional argument
// of a default accumulator. If myReduce only receives one argument, then
// myReduce will use the first element as the accumulator.
Array.prototype.myReduce = function(callback, acc) {
if (!acc) {
acc = this.shift();
}
this.forEach(function(element) {
acc = callback(acc, element)
})
return acc;
}Copyright © 2021 Codeinu
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