Answers for "js how to sort array of objects"

sort array of object js

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0));

javascript sort array with objects

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first

sort array with objects

const list = [
  { color: 'white', size: 'XXL' },
  { color: 'red', size: 'XL' },
  { color: 'black', size: 'M' }
]

var sortedArray = list.sort((a, b) => (a.color > b.color) ? 1 : -1)

// Result:
//sortedArray:
//{ color: 'black', size: 'M' }
//{ color: 'red', size: 'XL' }
//{ color: 'white', size: 'XXL' }

sort array of objects javascript

list.sort((a, b) => (a.color > b.color) ? 1 : -1)

javascript sort array of objects

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

compareObjects(object1, object2, key) {
  const obj1 = object1[key].toUpperCase()
  const obj2 = object2[key].toUpperCase()

  if (obj1 < obj2) {
    return -1
  }
  if (obj1 > obj2) {
    return 1
  }
  return 0
}

books.sort((book1, book2) => {
  return compareObjects(book1, book2, 'name')
})

// Result:
// {id: 2, name: 'A Tale of Two Cities'}
// {id: 3, name: 'Don Quixote'}
// {id: 4, name: 'The Hobbit'}
// {id: 1, name: 'The Lord of the Rings'}

js sort array of objects

const drinks1 = [
	{name: 'lemonade', price: 90}, 
	{name: 'lime', price: 432}, 
	{name: 'peach', price: 23}
];

function sortDrinkByPrice(drinks) {
	return drinks.sort((a, b) => a.price - b.price);
}