typescript sort array of objects
const list = [
{ color: 'white', size: 'XXL' },
{ color: 'red', size: 'XL' },
{ color: 'black', size: 'M' }
]
list.sort((a, b) => (a.color > b.color) ? 1 : -1)typescript sort array of objects
const list = [
{ color: 'white', size: 'XXL' },
{ color: 'red', size: 'XL' },
{ color: 'black', size: 'M' }
]
list.sort((a, b) => (a.color > b.color) ? 1 : -1)sort by object property javascript
let list = [
{
name: "world"
},
{
name: "hello",
},
];
// This doesn't account for if names are the same between objects
let x = list.sort((a, b) => (a.name > b.name ? 1 : -1));
console.log(x);
/*
[
{
name: "hello",
},
{
name: "world"
},
];
*/javascript sort array with objects
var array = [
{name: "John", age: 34},
{name: "Peter", age: 54},
{name: "Jake", age: 25}
];
array.sort(function(a, b) {
return a.age - b.age;
}); // Sort youngest firsthow to sort an array of objects by a property value in javascript
let x = list.sort((a, b) => (a.name > b.name ? 1 : -1));javascript sort array of objects
const books = [
{id: 1, name: 'The Lord of the Rings'},
{id: 2, name: 'A Tale of Two Cities'},
{id: 3, name: 'Don Quixote'},
{id: 4, name: 'The Hobbit'}
]
compareObjects(object1, object2, key) {
const obj1 = object1[key].toUpperCase()
const obj2 = object2[key].toUpperCase()
if (obj1 < obj2) {
return -1
}
if (obj1 > obj2) {
return 1
}
return 0
}
books.sort((book1, book2) => {
return compareObjects(book1, book2, 'name')
})
// Result:
// {id: 2, name: 'A Tale of Two Cities'}
// {id: 3, name: 'Don Quixote'}
// {id: 4, name: 'The Hobbit'}
// {id: 1, name: 'The Lord of the Rings'}sort array of objects by string property value
function compareFirstNames( a, b ) {
if ( a.first_name < b.first_name ){
return -1;
}
if ( a.first_name > b.first_name ){
return 1;
}
return 0;
}
var people =[
{"first_name":"Carol", "age":29},
{"first_name":"Anna", "age":32},
{"first_name":"Bob", "age":32}
];
people.sort( compareFirstNames ); //people is now sorted by first name from a-zCopyright © 2021 Codeinu
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