sort by object property javascript
let list = [
{
name: "world"
},
{
name: "hello",
},
];
// This doesn't account for if names are the same between objects
let x = list.sort((a, b) => (a.name > b.name ? 1 : -1));
console.log(x);
/*
[
{
name: "hello",
},
{
name: "world"
},
];
*/javascript sort array with objects
var array = [
{name: "John", age: 34},
{name: "Peter", age: 54},
{name: "Jake", age: 25}
];
array.sort(function(a, b) {
return a.age - b.age;
}); // Sort youngest firstjavascript sort object js
grossaryList = {
'bread': 1,
'apple': 6,
'milk': 1,
'orange': 3,
'broccoli': 2
}
return Object
.entries(grossaryList)
.sort((a,b) => b[1]-a[1])
//=> [['apple', 6],['orange', 3],['broccoli', 2],['bread',1],['milk', 1]]javascript sort array of objects
const books = [
{id: 1, name: 'The Lord of the Rings'},
{id: 2, name: 'A Tale of Two Cities'},
{id: 3, name: 'Don Quixote'},
{id: 4, name: 'The Hobbit'}
]
compareObjects(object1, object2, key) {
const obj1 = object1[key].toUpperCase()
const obj2 = object2[key].toUpperCase()
if (obj1 < obj2) {
return -1
}
if (obj1 > obj2) {
return 1
}
return 0
}
books.sort((book1, book2) => {
return compareObjects(book1, book2, 'name')
})
// Result:
// {id: 2, name: 'A Tale of Two Cities'}
// {id: 3, name: 'Don Quixote'}
// {id: 4, name: 'The Hobbit'}
// {id: 1, name: 'The Lord of the Rings'}javascript sort array of objects by key value
arr.sort((x, y) => x.distance - y.distance);sort array of objects javascript by value
let orders = [
{
order: 'order 1', date: '2020/04/01_11:09:05'
},
{
order: 'order 2', date: '2020/04/01_10:29:35'
},
{
order: 'order 3', date: '2020/04/01_10:28:44'
}
];
console.log(orders);
orders.sort(function(a, b){
let dateA = a.date.toLowerCase();
let dateB = b.date.toLowerCase();
if (dateA < dateB)
{
return -1;
}
else if (dateA > dateB)
{
return 1;
}
return 0;
});
console.log(orders);Copyright © 2021 Codeinu
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