Create a class complex that contains two double data members. Overload +, -, and * arithmetic operators, so that they can operate on the object of complex. Then find the expression a-b*c + d (where a, b, c, and d are complex objects).
#include<iostream.h>
#include<conio.h>
class FLOAT
{
float no;
public:
FLOAT(){}
void getdata()
{
cout<<"\n ENTER AN FLOATING NUMBER :";
cin>>no;
}
void putdata()
{
cout<<"\n\nANSWER IS :"<<no;
}
FLOAT operator+(FLOAT);
FLOAT operator*(FLOAT);
FLOAT operator-(FLOAT);
FLOAT operator/(FLOAT);
};
FLOAT FLOAT::operator+(FLOAT a)
{
FLOAT temp;
temp.no=no+a.no;
return temp;
}
FLOAT FLOAT::operator*(FLOAT b)
{
FLOAT temp;
temp.no=no*b.no;
return temp;
}
FLOAT FLOAT::operator-(FLOAT b)
{
FLOAT temp;
temp.no=no-b.no;
return temp;
}
FLOAT FLOAT::operator/(FLOAT b)
{
FLOAT temp;
temp.no=no/b.no;
return temp;
}
main()
{
clrscr();
FLOAT a,b,c;
a.getdata();
b.getdata();
c=a+b;
cout<<"\n\nAFTER ADDITION OF TWO OBJECTS";
c.putdata();
cout<<"\n\nAFTER MULTIPLICATION OF TWO OBJECTS";
c=a*b;
c.putdata();
cout<<"\n\nAFTER SUBSTRACTION OF TWO OBJECTS";
c=a-b;
c.putdata();
cout<<"\n\nAFTER DIVISION OF TWO OBJECTS";
c=a/b;
c.putdata();
getch();
}