Answers for "mdn for..of"

Javascript

0

mdn for..of

function* fibonacci() { // a generator function
  let [prev, curr] = [0, 1];
  while (true) {
    [prev, curr] = [curr, prev + curr];
    yield curr;
  }
}

for (const n of fibonacci()) {
  console.log(n);
  // truncate the sequence at 1000
  if (n >= 1000) {
    break;
  }
}

Posted by: Guest on January-08-2021

Source

Code answers related to "mdn for..of"

Code answers related to "Javascript"

Javascript Answers by Framework

Browse Popular Code Answers by Language

Python

Javascript

Whatever

Shell/Bash

CSS

Html

PHP

SQL

Java

C#